The graph is a nice way of doing it, but logically the line you plot should always extrapolate to zero tidal stream for zero coefficient. Therefore the sum reduces to rate=rate at springs x coeff /.95, gives 2.65 in your example. Just remember that the coeffs are only predictions so will be wrong due to weather effects. I would have just said that it was halfway between neaps and springs! Also there is no guarantee that the direction will be quite the same in neaps and springs. There can be a bit of a reality gap with the exam, but you have to show you understand the data as it is presented in the almaniac, and you're able to process it effectively.
|